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Hi !
I've just visited this forum. Happy to get acquainted with you. Thanks. 

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You have wood for the trees problems. If I was a large piece of iron and someone was kind enough to add a 1.5 V battery and some copper wire to various parts of my anatomy, I would have an effect on magnetically attractive objects in my local area. As these objects were forced to change there positions due to this new demand on their time they would have inadvertently created energy, which I believe could be harvested.

Why is that then? Well, using Newton's equation for potential energy and gravitation as an example: Energy=Height X Mass X Gravity. This would give me an amount in Joules; now as my attraction is as much as half a ton, I could theoretically pull a large object on a dynamo device towards me, using the Newtonian Laws for Potential energy and a way of orbiting my magnetic attraction, I am convinced the harvest would exceed the 1.5V investment.

However, I take on board what you have said, but you get lost in the conservation of energy debate, when it isn't part of the process at all, it's purely down to harvesting potential energy from a moving object, similar to the Moon going around the Earth. and then using it as a dynamo, it is simply constantly attracted to my a magnetic source, and I can harvest its potential.

Thanks for your reply.

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Hi, I'm Isa!
I hope I can exchange ideas here!

I'm Reg - retired physicist but still researching. 

Yea - like taxes, inevitably you've got to pay

Hi Chris!  Thanks for posting here.

Because no one has replied to this I thought it would be an idea to do so.

Unfortunately your assumption that somehow you will derive more energy than you put into it is wrong. The opposite is actually true. To keep the device spinning you need to overcome friction and heating losses. This means you will get less energy from it than you put into it. Remember the generator coil on the back of the "turbine" consumes power and therefore is hard to make turn. If that wasn't so, we could all have a hand generator in our electric car and as long as we kept turning it the car would run. Turning that hand generator would be as hard as pushing the car all the way to our destination.

To understand better imagine an electric motor that in turn drives an electric generator which charges a battery. If both the motor and the generator and the battery and all the circuits in between where 100% efficient. then you would get out of it exactly what you put into it. So you could connect the battery to the motor which turned the generator which kept the battery charged which kept the motor running... just! there would not be a milliamp left over for anything else.

But sadly nothing is perfect. a lot of loss occurs along the way. therefore the battery is never quite charged enough and the motor draws more power out of it than is going into it.

Eventually (actually quite soon) the battery will totally discharge and the whole thing will stop. there would be no leftover power for anything else.

Of course that assumes you had a fully charged battery to start with.

DC

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Hi

Assuming you mean a pressure gauge, it should read the same anywhere in a vacuum chamber, except possibly while pumping the air out if you have the gauge close to the pump (or likewise if there is a leak & it is near the leak). If nothing is changing it should be the same everywhere.